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    T113烧录R528的img文件失败

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    • W
      wxgd2017 LV 5 last edited by

      T113和R528是同一个die,但是用R528的tina 打包的img无法烧录到T113,提示检查文件有效性和设备是否正常工作,有人尝试吗?

      YuzukiTsuru 1 Reply Last reply Reply Quote Share 0
      • cube_work
        cube_work LV 5 last edited by

        都是DDR3吗?

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        • YuzukiTsuru
          柚木 鉉 LV 9 @wxgd2017 last edited by YuzukiTsuru

          @wxgd2017 全志平台的brandy里有芯片验证代码,R528和T113虽然是一个Die,但是其烧录的验证代码是不一样的,所以不能启动。

          可以在直接在brandy的build.sh里面把传进来的值强制赋值成T113,不过这个要自己研究了

          或者下载T113的SDK替换brandy

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          • xiaowenge
            DOT小文哥 LV 8 last edited by

            chip ID不一样=不是一颗芯片,不用试,烧不进去的

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            • T
              tripod9 LV 5 @xiaowenge last edited by

              @xiaowenge 芯片验证代码能找到机关吗?xfel现在找一个方法来判断各种马甲

              YuzukiTsuru 1 Reply Last reply Reply Quote Share 0
              • YuzukiTsuru
                柚木 鉉 LV 9 @tripod9 last edited by

                @tripod9 lichee\brandy-2.0\spl\board\r528\libsunxxx.a 里

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                • T
                  tripod9 LV 5 @YuzukiTsuru last edited by

                  @yuzukitsuru
                  找到个这个函数,是R528里面的,id_judge_fun,有谁发现什么机关,需要找多个平台的id_judge_fun函数来对比,估计才能看出名堂。

                  
                  uint id_judge_fun(uint param_1)
                  
                  {
                    uint uVar1;
                    
                    if ((_DAT_01c15004 & 7) == 0) {
                      uVar1 = disturb_coding(param_1,1);
                      return uVar1;
                    }
                    return 0;
                  }
                  
                  
                  
                  uint disturb_coding(uint param_1,int param_2)
                  
                  {
                    int iVar1;
                    
                    iVar1 = crc_16(param_1,param_2);
                    return param_1 + param_2 | iVar1 << 0x10;
                  }
                  
                  
                  
                  void crc_16(uint param_1,int param_2)
                  
                  {
                    uint uVar1;
                    uint uVar2;
                    short sVar3;
                    
                    uVar1 = param_1 ^ param_2 << 8;
                    sVar3 = 8;
                    do {
                      uVar2 = uVar1 & 0x8000;
                      uVar1 = (uVar1 & 0x7fff) << 1;
                      if (uVar2 != 0) {
                        uVar1 = (uVar1 ^ 0xffff8005) & 0xffff;
                      }
                      sVar3 = sVar3 + -1;
                    } while (sVar3 != 0);
                    return;
                  }
                  
                  
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